A student took five papers in an examination, where the maximum marks were same for each paper. His marks in these papers were in the proportion of 3: 4: 9: 11: 13. In all papers together, the candidate obtained 60% of the total marks. Then, the number of papers in which he got less than 70% marks is .1234

To solve this problem, we first need to understand the proportion of marks the student got in each paper. The proportions are 3:4:9:11:13.

Step 1: Add up the proportions. 3 + 4 + 9 + 11 + 13 = 40

Step 2: Since the student scored 60% in all papers together, we can say that 60% of the total marks is equivalent to 40 (the sum of the proportions).

Step 3: Now, we need to find out what 1 proportion is equivalent to in terms of percentage. 60% / 40 = 1.5%

Step 4: Now, we need to find out the percentage of marks the student got in each paper. For the first paper, 3 * 1.5% = 4.5% For the second paper, 4 * 1.5% = 6% For the third paper, 9 * 1.5% = 13.5% For the fourth paper, 11 * 1.5% = 16.5% For the fifth paper, 13 * 1.5% = 19.5%

Step 5: Now, we need to find out the number of papers in which he got less than 70% marks. From the percentages calculated above, we can see that the student got less than 70% marks in all five papers.

So, the number of papers in which he got less than 70% marks is 5.

To solve this problem, we first need to understand the proportion of marks the student got in each paper. The proportions are 3:4:9:11:13.

Step 1: Add up the proportions. 3 + 4 + 9 + 11 + 13 = 40

Step 2: Since the student scored 60% in all papers together, we can say that 60% of the total marks is equal to the sum of the proportions.

Step 3: To find out the percentage of marks the student got in each paper, we divide the individual proportion by the total proportion and multiply by 100.

For the first paper, (3/40)*100 = 7.5% For the second paper, (4/40)*100 = 10% For the third paper, (9/40)*100 = 22.5% For the fourth paper, (11/40)*100 = 27.5% For the fifth paper, (13/40)*100 = 32.5%

Step 4: Now, we need to find out the number of papers in which he got less than 70% marks.

From the percentages calculated above, we can see that the student scored less than 70% in all five papers. Therefore, the number of papers in which he got less than 70% marks is 5.

To solve this problem, we first need to understand the proportion of marks the student got in each paper. The proportions are 3:4:9:11:13.

Step 1: Add up the proportions. 3 + 4 + 9 + 11 + 13 = 40

Step 2: Since the student scored 60% in all papers together, we can say that 60% of the total marks is equal to the sum of the proportions, which is 40.

Step 3: Now, we need to find out the percentage of marks the student got in each paper. To do this, we divide the proportion of each paper by the total proportion (40) and then multiply by 100.

For the first paper: (3/40)*100 = 7.5% For the second paper: (4/40)*100 = 10% For the third paper: (9/40)*100 = 22.5% For the fourth paper: (11/40)*100 = 27.5% For the fifth paper: (13/40)*100 = 32.5%

Step 4: We are asked to find the number of papers in which the student got less than 70% marks. From the percentages we calculated, we can see that the student got less than 70% in all five papers.

So, the answer is 5.

To solve this problem, we first need to understand the proportion of marks the student got in each paper. The proportions are 3:4:9:11:13.

Step 1: Add up the proportions. 3 + 4 + 9 + 11 + 13 = 40

Step 2: Since the student scored 60% in all papers together, we can say that each unit of the proportion is equal to 1.5% (60% / 40).

Step 3: Now, we need to find out in how many papers the student scored less than 70%.

• In the first paper, the student scored 3 * 1.5% = 4.5%.
• In the second paper, the student scored 4 * 1.5% = 6%.
• In the third paper, the student scored 9 * 1.5% = 13.5%.
• In the fourth paper, the student scored 11 * 1.5% = 16.5%.
• In the fifth paper, the student scored 13 * 1.5% = 19.5%.

Step 4: Comparing these percentages with 70%, we can see that the student scored less than 70% in all five papers.

So, the number of papers in which he got less than 70% marks is 5.

To solve this problem, we first need to understand the proportion of marks the student got in each paper. The proportions are 3:4:9:11:13.

Step 1: Add up the proportions. 3 + 4 + 9 + 11 + 13 = 40

Step 2: Since the student scored 60% in total, we can assume the total marks for each paper is 100 (as it's mentioned that maximum marks were same for each paper). So, the total marks for all five papers would be 500.

Step 3: The student scored 60% of the total marks. So, the marks he scored in total is 60% of 500 = 300 marks.

Step 4: Now, we know that the 40 units (from the proportion) is equal to 300 marks (the total marks the student got). So, 1 unit would be equal to 300/40 = 7.5 marks.

Step 5: Now, we can calculate the marks the student got in each paper by multiplying the unit value with the proportion.

• Paper 1: 3 * 7.5 = 22.5 marks
• Paper 2: 4 * 7.5 = 30 marks
• Paper 3: 9 * 7.5 = 67.5 marks
• Paper 4: 11 * 7.5 = 82.5 marks
• Paper 5: 13 * 7.5 = 97.5 marks

Step 6: Now, we need to find out in how many papers the student got less than 70% marks. 70% of 100 marks is 70 marks. So, we compare each paper's marks with 70.

• Paper 1: 22.5 marks < 70 marks
• Paper 2: 30 marks < 70 marks
• Paper 3: 67.5 marks < 70 marks
• Paper 4: 82.5 marks > 70 marks
• Paper 5: 97.5 marks > 70 marks

So, the student got less than 70% marks in 3 papers.

To solve this problem, we first need to understand the proportion of marks the student got in each paper. The proportions are 3:4:9:11:13.

Step 1: Add up the proportions. 3 + 4 + 9 + 11 + 13 = 40

Step 2: Since the student scored 60% in all papers together, we can say that 40 parts is equal to 60%.

Step 3: To find out what 1 part is equal to, we divide 60 by 40. 60/40 = 1.5. So, 1 part is equal to 1.5%.

Step 4: Now, we need to find out the percentage of marks the student got in each paper. We multiply the number of parts by 1.5.

• Paper 1: 3 parts * 1.5 = 4.5%
• Paper 2: 4 parts * 1.5 = 6%
• Paper 3: 9 parts * 1.5 = 13.5%
• Paper 4: 11 parts * 1.5 = 16.5%
• Paper 5: 13 parts * 1.5 = 19.5%

Step 5: We need to find out the number of papers in which the student got less than 70% marks. From the percentages we calculated, we can see that the student got less than 70% in all five papers.

So, the student got less than 70% marks in 5 papers.

To solve this problem, we first need to understand the proportion of marks the student got in each paper. The proportions are 3:4:9:11:13.

Step 1: Add up the proportions. 3 + 4 + 9 + 11 + 13 = 40

Step 2: Since the student scored 60% in all papers together, we can say that each proportion point is equal to 1.5% (60% / 40).

Step 3: Now, we need to find out how many papers the student scored less than 70% in.

• In the first paper, the student scored 3 * 1.5% = 4.5%
• In the second paper, the student scored 4 * 1.5% = 6%
• In the third paper, the student scored 9 * 1.5% = 13.5%
• In the fourth paper, the student scored 11 * 1.5% = 16.5%
• In the fifth paper, the student scored 13 * 1.5% = 19.5%

Step 4: Compare these percentages with 70%.

The student scored less than 70% in all five papers. Therefore, the number of papers in which he got less than 70% marks is 5.