Let's denote the marks of the two students as x and y.

According to the problem, one student has 9 marks more than the other. We can express this as:

x = y + 9

The problem also states that the marks of one student is 56% of the sum of their marks. We can express this as:

x = 0.56 * (x + y)

Now we have a system of two equations, and we can solve it step by step.

First, substitute x from the first equation into the second equation:

y + 9 = 0.56 * ((y + 9) + y)

Simplify the equation:

y + 9 = 0.56 * (2y + 9)

Expand the right side:

y + 9 = 1.12y + 5.04

Rearrange the equation:

0.12y = 3.96

Finally, solve for y:

y = 3.96 / 0.12 = 33

Substitute y = 33 into the first equation to find x:

x = y + 9 = 33 + 9 = 42

So, the marks obtained by the two students are 33 and 42.

Question

Let's denote the marks of the two students as x and y.

According to the problem, one student has 9 marks more than the other. We can express this as:

x = y + 9

The problem also states that the marks of one student is 56% of the sum of their marks. We can express this as:

x = 0.56 * (x + y)

Now we have a system of two equations, and we can solve it step by step.

First, substitute x from the first equation into the second equation:

y + 9 = 0.56 * ((y + 9) + y)

Simplify the equation:

y + 9 = 0.56 * (2y + 9)

Expand the right side:

y + 9 = 1.12y + 5.04

Rearrange the equation:

0.12y = 3.96

Finally, solve for y:

y = 3.96 / 0.12 = 33

Substitute y = 33 into the first equation to find x:

x = y + 9 = 33 + 9 = 42

So, the marks obtained by the two students are 33 and 42.

Knowee AI · Accepted Answer