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A boy scores an aggregate of 70% marks, scoring an average of 62% in 4 of the papers and 78% in the other papers. How many papers were there totallyOptions85107

Question

A boy scores an aggregate of 70% marks, scoring an average of 62% in 4 of the papers and 78% in the other papers. How many papers were there totallyOptions85107

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Solution

Let's solve this step by step:

  1. Let's assume the total number of papers is 'x'.

  2. According to the problem, the boy scores an average of 62% in 4 of the papers. So, the total percentage for these 4 papers is 4*62 = 248%.

  3. The boy scores an average of 78% in the remaining papers. So, the total percentage for these papers is 78*(x-4).

  4. The aggregate score of 70% is the average score across all papers. So, the total percentage for all papers is 70*x.

  5. According to the problem, the total percentage for all papers is the sum of the total percentage for the first 4 papers and the total percentage for the remaining papers. So, we can set up the equation: 70x = 248 + 78*(x-4).

  6. Solving this equation will give us the total number of papers 'x'.

  7. 70x = 248 + 78x - 312

  8. Simplifying gives: 8x = 64

  9. Solving for x gives: x = 8

So, the total number of papers is 8.

This problem has been solved

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