The energy needed to increase the temperature of 1.5 kg of brick by 70 °C was 88 305 J.Calculate the specific heat capacity of glass._________ J/kg°CYou do not need to include units in your answer.
Question
The energy needed to increase the temperature of 1.5 kg of brick by 70 °C was 88 305 J.Calculate the specific heat capacity of glass._________ J/kg°CYou do not need to include units in your answer.
Solution 1
The question seems to be a bit confused. You're asking for the specific heat capacity of glass, but you've provided data for a brick. The specific heat capacity is a property that is specific to the material, so we can't use data for a brick to calculate the specific heat capacity of glass.
However, if you want to calculate the specific heat capacity of the brick with the data provided, you can use the formula:
Q = mcΔT
where: Q = heat energy absorbed or released (in joules), which is 88 305 J m = mass of the substance (in kilograms), which is 1.5 kg ΔT = change in temperature (in Celsius degrees), which is 70 °C c = specific heat capacity (in J/kg°C), which is what we're trying to find
Rearranging the formula to find c gives us:
c = Q / (m * ΔT)
Substituting the given values into this formula will give us the specific heat capacity of the brick.
Solution 2
The question seems to have a mistake. It asks for the specific heat capacity of glass, but the data provided is for a brick. If we assume that the question meant to ask for the specific heat capacity of the brick, we can use the formula for heat transfer:
Q = mcΔT
where: Q = heat energy absorbed or released (in joules) m = mass (in kg) c = specific heat capacity (in J/kg°C) ΔT = change in temperature (in °C)
We can rearrange the formula to solve for c:
c = Q / (mΔT)
Substituting the given values:
c = 88,305 J / (1.5 kg * 70 °C) = 842 J/kg°C
So, the specific heat capacity of the brick (assuming that's what the question meant to ask for) is 842 J/kg°C.
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