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1What is meant by the specific heat capacity of a material?The amount of energy required to raise the temperature of 1 kilogram of the material by 1 degree CelsiusThe amount of energy which is required to change 1 kilogram of the material from a liquid to a gasThe total amount of thermal energy which can be stored by 1 kilogram of the materialThe amount of energy which is required to change 1 kilogram of the material from a solid to a liquid2The specific heat capacity of water is 4200 J/kg °C.  Calculate the amount of energy required to raise the temperature of 500 g of water from 20 to 70 °C.147 kJ105 MJ (105,000,000 J)147 MJ (147,000,000 J)105 kJ3A heater is used to transfer 40 kJ of energy to the thermal store of a 2 kg copper cylinder.  By how much will this cause the temperature of the copper to increase?  The specific heat capacity of copper is 385 J/kg °C.0.05 °C51.9 °C207.8 °C0.21 °C

Question

1What is meant by the specific heat capacity of a material?The amount of energy required to raise the temperature of 1 kilogram of the material by 1 degree CelsiusThe amount of energy which is required to change 1 kilogram of the material from a liquid to a gasThe total amount of thermal energy which can be stored by 1 kilogram of the materialThe amount of energy which is required to change 1 kilogram of the material from a solid to a liquid2The specific heat capacity of water is 4200 J/kg °C.  Calculate the amount of energy required to raise the temperature of 500 g of water from 20 to 70 °C.147 kJ105 MJ (105,000,000 J)147 MJ (147,000,000 J)105 kJ3A heater is used to transfer 40 kJ of energy to the thermal store of a 2 kg copper cylinder.  By how much will this cause the temperature of the copper to increase?  The specific heat capacity of copper is 385 J/kg °C.0.05 °C51.9 °C207.8 °C0.21 °C

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Solution

  1. The specific heat capacity of a material is the amount of energy required to raise the temperature of 1 kilogram of the material by 1 degree Celsius.

  2. To calculate the amount of energy required to raise the temperature of 500 g of water from 20 to 70 °C, we use the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

First, convert the mass from grams to kilograms: 500 g = 0.5 kg.

Then, calculate the change in temperature: 70 °C - 20 °C = 50 °C.

Finally, substitute these values into the formula: Q = 0.5 kg * 4200 J/kg°C * 50 °C = 105,000 J, or 105 kJ.

So, the amount of energy required is 105 kJ.

  1. To calculate the temperature increase of a 2 kg copper cylinder when a heater transfers 40 kJ of energy to it, we use the formula ΔT = Q/(mc), where ΔT is the change in temperature, Q is the heat energy, m is the mass, and c is the specific heat capacity.

First, convert the energy from kJ to J: 40 kJ = 40,000 J.

Then, substitute these values into the formula: ΔT = 40,000 J / (2 kg * 385 J/kg°C) = 51.9 °C.

So, the temperature of the copper will increase by 51.9 °C.

This problem has been solved

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