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Specific heat capacity of water is 4200 J/kg⁰C. How much energy is needed to raise thetemperature of 3kg of water by 4⁰C?

Question

Specific heat capacity of water is 4200 J/kg⁰C. How much energy is needed to raise thetemperature of 3kg of water by 4⁰C?

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Solution

To calculate the energy needed to raise the temperature of a certain amount of water, we can use the formula:

Q = mcΔT

where:

  • Q is the heat energy (in Joules)
  • m is the mass of the substance (in kg)
  • c is the specific heat capacity (in J/kg°C)
  • ΔT is the change in temperature (in °C)

Given:

  • m = 3 kg
  • c = 4200 J/kg°C
  • ΔT = 4°C

Substitute these values into the formula:

Q = 3 kg * 4200 J/kg°C * 4°C = 50400 J

So, 50400 Joules of energy is needed to raise the temperature of 3 kg of water by 4°C.

This problem has been solved

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