he specific heat capacity of water is 4.2 kJ/kg°C.Calculate the energy required to increase the temperature of 0.60 kg of water from 31°C to 56°C.
Question
he specific heat capacity of water is 4.2 kJ/kg°C.Calculate the energy required to increase the temperature of 0.60 kg of water from 31°C to 56°C.
Solution
The energy required can be calculated using the formula:
Q = mcΔT
where: Q = heat energy m = mass c = specific heat capacity ΔT = change in temperature
Given: m = 0.60 kg c = 4.2 kJ/kg°C ΔT = 56°C - 31°C = 25°C
Substituting the given values into the formula:
Q = (0.60 kg) * (4.2 kJ/kg°C) * (25°C) = 63 kJ
So, the energy required to increase the temperature of 0.60 kg of water from 31°C to 56°C is 63 kJ.
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