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A student heats up impure water from 40 °C to 60 °C with the thermal energy of 5,000J, the heat capacity of the water would be:Question 17Answera.−125 J K-1b.−250 J K-1c.250 J K-1d.125 J K-1

Question

A student heats up impure water from 40 °C to 60 °C with the thermal energy of 5,000J, the heat capacity of the water would be:Question 17Answera.−125 J K-1b.−250 J K-1c.250 J K-1d.125 J K-1

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Solution

The heat capacity (C) of a substance is the amount of heat energy required to raise the temperature of the substance by one degree. It can be calculated using the formula:

C = Q / ΔT

where: Q is the amount of heat energy supplied, and ΔT is the change in temperature.

Given: Q = 5,000 J, and ΔT = 60°C - 40°C = 20 K (since the Celsius and Kelvin scales are linearly related).

Substituting these values into the formula, we get:

C = 5,000 J / 20 K = 250 J K^-1.

So, the heat capacity of the water is 250 J K^-1. The correct answer is c. 250 J K^-1.

This problem has been solved

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