When 860J of heat energy is supplied to a 0.4kg of a substance, its temperature rises from 250C to 500C. What is the specific heat capacity of this substance?Question 24Answera.120J/kg kb.172 J/kg kc.86J/kg kd.43J/kg k
Question
When 860J of heat energy is supplied to a 0.4kg of a substance, its temperature rises from 250C to 500C. What is the specific heat capacity of this substance?Question 24Answera.120J/kg kb.172 J/kg kc.86J/kg kd.43J/kg k
Solution
The specific heat capacity (c) of a substance is the amount of heat energy required to raise the temperature of one kilogram of the substance by one degree. It can be calculated using the formula:
c = Q / (m * ΔT)
where: Q is the amount of heat energy supplied, m is the mass of the substance, and ΔT is the change in temperature.
Given: Q = 860 J, m = 0.4 kg, and ΔT = 50°C - 25°C = 25 K (since the Celsius and Kelvin scales are linearly related).
Substituting these values into the formula, we get:
c = 860 J / (0.4 kg * 25 K) = 860 J / 10 kg K = 86 J/kg K.
So, the specific heat capacity of the substance is 86 J/kg K. The correct answer is c. 86J/kg K.
Similar Questions
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