The energy needed to increase the temperature of 0.7 kg of glass by 30 °C was 16 632 J.Calculate the specific heat capacity of glass._________ J/kg°CYou do not need to include units in your answer.
Question
The energy needed to increase the temperature of 0.7 kg of glass by 30 °C was 16 632 J.Calculate the specific heat capacity of glass._________ J/kg°CYou do not need to include units in your answer.
Solution
The specific heat capacity (c) of a substance can be calculated using the formula:
Q = mcΔT
where: Q = heat energy absorbed or released (in joules, J) m = mass of the substance (in kilograms, kg) c = specific heat capacity (in joules per kilogram per degree Celsius, J/kg°C) ΔT = change in temperature (in degrees Celsius, °C)
In this case, we are given: Q = 16,632 J m = 0.7 kg ΔT = 30 °C
We are asked to find c. Rearranging the formula to solve for c gives us:
c = Q / (mΔT)
Substituting the given values into this formula gives us:
c = 16,632 J / (0.7 kg * 30 °C) = 793.90476 J/kg°C
So, the specific heat capacity of the glass is approximately 793.9 J/kg°C.
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