The specific heat of Pyrex glass is 0.78 J g-1 °C-1. Calculate the heat, q, required when 1.15 g of glass is heated from 34 °C to 65 °C . Give your answer in J with 2 significant figures. Do not include units.
Question
The specific heat of Pyrex glass is 0.78 J g-1 °C-1. Calculate the heat, q, required when 1.15 g of glass is heated from 34 °C to 65 °C . Give your answer in J with 2 significant figures. Do not include units.
Solution
To calculate the heat (q) required, we can use the formula:
q = mcΔT
where: m = mass of the substance (in grams) c = specific heat capacity (in J/g°C) ΔT = change in temperature (in °C)
Given: m = 1.15 g c = 0.78 J/g°C ΔT = 65°C - 34°C = 31°C
Substituting these values into the formula:
q = (1.15 g)(0.78 J/g°C)(31°C)
q = 27.867 J
Rounding to two significant figures, the heat required is 28 J.
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