The equation of a circle in standard form is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

In the given equation (x - 2)² + (y - 3)² = 9, you can see that it's in the same form.

So, by comparing, we can find:

h = 2, k = 3, and r² = 9.

This means the center of the circle is at (2, 3) and the radius of the circle is √9 = 3.

Question

The equation of a circle in standard form is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

In the given equation (x - 2)² + (y - 3)² = 9, you can see that it's in the same form.

So, by comparing, we can find:

h = 2, k = 3, and r² = 9.

This means the center of the circle is at (2, 3) and the radius of the circle is √9 = 3.

Knowee AI · Accepted Answer

The equation of a circle in standard form is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

In the given equation (x - 2)² + (y - 3)² = 9, you can see that it's in the same form.

So, by comparing, we can find:

h = 2, k = 3, and r² = 9.

This means the center of the circle is at (2, 3) and the radius of the circle is √9 = 3.

What is the center and the radius of the circle: ( x - 2 )2 + ( y - 3 )2 = 9?