The center of the circle is given by the values in the equation (x-h)² + (y-k)² = r², where (h,k) are the coordinates of the center and r is the radius.

In the given equation, (x−2)² + y² = 36, we can see that h=2 and k=0. So, the center of the circle is (2,0).

The radius of the circle is the square root of the number on the right side of the equation. In this case, the radius r is √36, which equals 6.

So, the center of the circle is (2,0) and the radius is 6.

Question

The center of the circle is given by the values in the equation (x-h)² + (y-k)² = r², where (h,k) are the coordinates of the center and r is the radius.

In the given equation, (x−2)² + y² = 36, we can see that h=2 and k=0. So, the center of the circle is (2,0).

The radius of the circle is the square root of the number on the right side of the equation. In this case, the radius r is √36, which equals 6.

So, the center of the circle is (2,0) and the radius is 6.

Knowee AI · Accepted Answer

The center of the circle is given by the values in the equation (x-h)² + (y-k)² = r², where (h,k) are the coordinates of the center and r is the radius.

In the given equation, (x−2)² + y² = 36, we can see that h=2 and k=0. So, the center of the circle is (2,0).

The radius of the circle is the square root of the number on the right side of the equation. In this case, the radius r is √36, which equals 6.

So, the center of the circle is (2,0) and the radius is 6.

1. What is the center and radius of the circle indicated by the equation?(x−2)2+y2=36

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