The equation of a circle in standard form is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the given equation x² + y² = 36, we can see that h and k are both 0 (because there are no terms subtracted from x² or y²). Therefore, the center of the circle is (0,0).

The radius of the circle is the square root of the number on the other side of the equation. In this case, √36 = 6.

So, the center of the circle is (0,0) and the radius is 6.

Therefore, the correct answer is c. Center = (0, 0) Radius = 6.

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The equation of a circle in standard form is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the given equation x² + y² = 36, we can see that h and k are both 0 (because there are no terms subtracted from x² or y²). Therefore, the center of the circle is (0,0).

The radius of the circle is the square root of the number on the other side of the equation. In this case, √36 = 6.

So, the center of the circle is (0,0) and the radius is 6.

Therefore, the correct answer is c. Center = (0, 0) Radius = 6.

Knowee AI · Accepted Answer

The equation of a circle in standard form is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the given equation x² + y² = 36, we can see that h and k are both 0 (because there are no terms subtracted from x² or y²). Therefore, the center of the circle is (0,0).

The radius of the circle is the square root of the number on the other side of the equation. In this case, √36 = 6.

So, the center of the circle is (0,0) and the radius is 6.

Therefore, the correct answer is c. Center = (0, 0) Radius = 6.

What is the center and the radius of the circle: x2 + y2 = 36?Question 5Select one:a.Center = (1, 1)Radius = 6b.Center = (1, 1)Radius = 36c.Center = (0, 0)Radius = 6d.Center = (0, 0)Radius = 36

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