The general equation of a circle is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is at (2, 3) and the radius is 6, we can substitute these values into the equation to get:

(x - 2)² + (y - 3)² = 6²

So, the equation of the circle is (x - 2)² + (y - 3)² = 36.

Question

The general equation of a circle is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is at (2, 3) and the radius is 6, we can substitute these values into the equation to get:

(x - 2)² + (y - 3)² = 6²

So, the equation of the circle is (x - 2)² + (y - 3)² = 36.

Knowee AI · Accepted Answer

The general equation of a circle is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is at (2, 3) and the radius is 6, we can substitute these values into the equation to get:

(x - 2)² + (y - 3)² = 6²

So, the equation of the circle is (x - 2)² + (y - 3)² = 36.

Find the equation of a circle with the center at (2, 3) and a radius of 6.