The equation of a circle in the standard form is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is (8, 6) and the radius is 5, we can substitute h = 8, k = 6, and r = 5 into the equation.

So, the equation of the circle is (x - 8)² + (y - 6)² = 5².

Simplifying further, we get the equation of the circle as (x - 8)² + (y - 6)² = 25.

Question

The equation of a circle in the standard form is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is (8, 6) and the radius is 5, we can substitute h = 8, k = 6, and r = 5 into the equation.

So, the equation of the circle is (x - 8)² + (y - 6)² = 5².

Simplifying further, we get the equation of the circle as (x - 8)² + (y - 6)² = 25.

Knowee AI · Accepted Answer

The equation of a circle in the standard form is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given that the center of the circle is (8, 6) and the radius is 5, we can substitute h = 8, k = 6, and r = 5 into the equation.

So, the equation of the circle is (x - 8)² + (y - 6)² = 5².

Simplifying further, we get the equation of the circle as (x - 8)² + (y - 6)² = 25.

What is the equation of a circle with center (8, 6) and radius 5?