What is the center of the circle given by the equation (x + 5)2 + (y - 8)2 = 1?

The center of the circle given by the equation (x + 5)² + (y - 8)² = 1 is at the point (-5, 8).

Here's the step-by-step explanation:

1. The general form of the equation of a circle is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

2. In the given equation, (x + 5)² + (y - 8)² = 1, you can see that it's in the same form, but with a '+' before the '5' and a '-' before the '8'.

3. This means that the 'h' value is -5 (because it's 'x - h', so 'x - (-5)' becomes 'x + 5') and the 'k' value is 8 (because it's 'y - k', so 'y - 8' gives 'k = 8').

4. Therefore, the center of the circle is at the point (-5, 8).