Find the center and radius of the circle.(x + 4)2 + (y - 4)2 = 4

The equation of a circle in standard form is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Given the equation (x + 4)² + (y - 4)² = 4, we can see that it is in the standard form.

The center of the circle (h, k) is given by the values that make (x - h) and (y - k) zero. In this case, h is -4 (since x is added to 4) and k is 4 (since y is subtracted from 4). So, the center of the circle is (-4, 4).

The radius of the circle is the square root of the right side of the equation. In this case, the radius r is √4 = 2.

So, the center of the circle is (-4, 4) and the radius is 2.