If 30.0 L of oxygen is cooled at constant pressure from 200oC to 1oC, what is the new volume of oxygen?Question 4Select one:a.0.150 Lb.17.4 Lc.23.0 Ld.51.8 Le.6.00 x 103 L

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas are kept constant. The formula for Charles's Law is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Step 1: Convert the temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = C + 273.15. So, T1 = 200°C + 273.15 = 473.15 K and T2 = 1°C + 273.15 = 274.15 K.

Step 2: Substitute the known values into Charles's Law and solve for V2.

V1/T1 = V2/T2

30.0 L / 473.15 K = V2 / 274.15 K

V2 = (30.0 L / 473.15 K) * 274.15 K

V2 = 17.4 L

So, the new volume of the oxygen at 1°C is approximately 17.4 L. Therefore, the correct answer is (b) 17.4 L.