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What is the volume of 0.98 mol oxygen (O2) gas at 275 K and a pressure of 2.0 atm?(The universal gas constant is 0.0821 L•atm/mol•K.)A.44 LB.11 LC.46 LD.0.090 L

Question

What is the volume of 0.98 mol oxygen (O2) gas at 275 K and a pressure of 2.0 atm?(The universal gas constant is 0.0821 L•atm/mol•K.)A.44 LB.11 LC.46 LD.0.090 L

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Solution

To solve this problem, we can use the ideal gas law equation, which is PV = nRT.

Where: P = pressure V = volume n = number of moles R = universal gas constant T = temperature

Given: P = 2.0 atm n = 0.98 mol R = 0.0821 L•atm/mol•K T = 275 K

We need to solve for V (volume).

Rearranging the equation to solve for V gives us V = nRT/P.

Substituting the given values into the equation gives us V = (0.98 mol * 0.0821 L•atm/mol•K * 275 K) / 2.0 atm.

Calculating this gives us V = 11.1 L.

So, the volume of 0.98 mol oxygen (O2) gas at 275 K and a pressure of 2.0 atm is approximately 11 L.

Therefore, the correct answer is B. 11 L.

This problem has been solved

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