The volume of a gas is 400.0 mL at 30.0oC. If the temperature is increased to 50oCwithout changing the pressure, what is the new volume of the gas?A.600 mLB.375 mLC.426 mLD.400 mL
Question
The volume of a gas is 400.0 mL at 30.0oC. If the temperature is increased to 50oCwithout changing the pressure, what is the new volume of the gas?A.600 mLB.375 mLC.426 mLD.400 mL
Solution
This problem can be solved using Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant. The formula for Charles's Law is V1/T1 = V2/T2, where:
- V1 is the initial volume
- T1 is the initial temperature
- V2 is the final volume
- T2 is the final temperature
Given in the problem:
- V1 = 400.0 mL
- T1 = 30.0°C = 303.15 K (converted from Celsius to Kelvin by adding 273.15)
- T2 = 50.0°C = 323.15 K (converted from Celsius to Kelvin by adding 273.15)
We need to find V2.
Substituting the given values into the formula, we get:
400.0 mL / 303.15 K = V2 / 323.15 K
Solving for V2, we get:
V2 = (400.0 mL / 303.15 K) * 323.15 K = 426.67 mL
So, the new volume of the gas at 50°C is approximately 426.67 mL. Therefore, the closest answer is C. 426 mL.
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