Here is a step-by-step guide to solve this problem:

1. First, you need to create a function that takes an integer as an input. Let's call this function `single_digit_sum`.

2. Inside this function, create a `while` loop. The condition for this loop should be that the number is greater than 9. This is because we want to keep summing the digits until we get a single-digit number.

3. Inside the `while` loop, convert the number to a string. This is because we want to be able to iterate over each digit in the number, and we can only do this if the number is a string.

4. Still inside the `while` loop, create a variable called `sum` and set it equal to 0. This variable will keep track of the sum of the digits.

5. Now, create a `for` loop that iterates over each digit in the number (which is now a string). For each digit, convert it back to an integer and add it to `sum`.

6. After the `for` loop, set the number equal to `sum`. This is because we want to repeat the process with the new number, which is the sum of the digits of the old number.

7. Once the `while` loop is done (i.e., once the number is a single-digit number), return the number.

8. Finally, outside the function, take an input from the user, pass it to the function, and print the result in the required format.

Here is a Python code snippet that implements the above steps:

```python
def single_digit_sum(n):
while n 9:
n = str(n)
sum = 0
for digit in n:
sum += int(digit)
n = sum
return n

n = int(input())
print("The single-digit sum of {} is {}.".format(n, single_digit_sum(n)))
```

This code will work for any positive integer n such that 1 ≤ n ≤ 1010.

Question

Here is a step-by-step guide to solve this problem:

1. First, you need to create a function that takes an integer as an input. Let's call this function `single_digit_sum`.

2. Inside this function, create a `while` loop. The condition for this loop should be that the number is greater than 9. This is because we want to keep summing the digits until we get a single-digit number.

3. Inside the `while` loop, convert the number to a string. This is because we want to be able to iterate over each digit in the number, and we can only do this if the number is a string.

4. Still inside the `while` loop, create a variable called `sum` and set it equal to 0. This variable will keep track of the sum of the digits.

5. Now, create a `for` loop that iterates over each digit in the number (which is now a string). For each digit, convert it back to an integer and add it to `sum`.

6. After the `for` loop, set the number equal to `sum`. This is because we want to repeat the process with the new number, which is the sum of the digits of the old number.

7. Once the `while` loop is done (i.e., once the number is a single-digit number), return the number.

8. Finally, outside the function, take an input from the user, pass it to the function, and print the result in the required format.

Here is a Python code snippet that implements the above steps:

```python
def single_digit_sum(n):
    while n > 9:
        n = str(n)
        sum = 0
        for digit in n:
            sum += int(digit)
        n = sum
    return n

n = int(input())
print("The single-digit sum of {} is {}.".format(n, single_digit_sum(n)))
```

This code will work for any positive integer n such that 1 ≤ n ≤ 1010.

Knowee AI · Accepted Answer