Problem StatementVivek wants to count the number of digits in the given integer and find the sum of the first and last digits of the number. Write a suitable program to complete the above task using a for loop.ExampleInput:1221Output:Sum = 2Digits = 4Explanation:Counting Digits: The number 1221 has 4 digits.First and Last Digits: The last digit is 1 (1221 % 10). To find the first digit, divide 1221 by 10 repeatedly until it's less than 10. The first digit is 1.The sum is 1 + 1 = 2.Note: This question helps in clearing coding technical tests for service-based companies.Input format :The input consists of an integer n.Output format :The first line prints "Sum = " followed by an integer which is the sum of the first and last digits.The second line prints "Digits = " followed by an integer which is the number of digits.Refer to the sample output for the formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:10 ≤ n ≤ 10000Sample test cases :Input 1 :1221Output 1 :Sum = 2Digits = 4Input 2 :10Output 2 :Sum = 1Digits = 2Input 3 :10000Output 3 :Sum = 1Digits = 5

Vivek wants to count the number of digits in the given integer and find the sum of the first and last digits of the number. Write a suitable program to complete the above task using a for loop.

James, a mathematics teacher, is developing a programming exercise to help his students practice continuously summing the digits of a number until it becomes a single-digit integer. He wants to create a simple program using a 'while' loop that takes a positive integer input and generates the final single-digit result. Input format :The input consists of a positive integer n.Output format :The output prints "The single-digit sum of n is Y." where n is the input integer and Y is its single-digit sum.Refer to the sample output for formatting specifications.Code constraints :1 ≤ n ≤ 1010Sample test cases :Input 1 :456Output 1 :The single-digit sum of 456 is 6.Input 2 :999Output 2 :The single-digit sum of 999

Write a C program to calculate sum of digits of a number. – using while loop

Given a positive integer 'x' (with even number of digits in it), write an algorithm and the subsequent code to compute the difference between  the sum of the digits occuring in the alternate positions (starting from the first position) and the sum of the digits occuring in the alternate positions,starting from the last rightmost position of 'x'For example, consider the number  8975.  The sum of the digits that occur in the alternate positions from the first position is 8+7=15.  The sum of the digits that occur in the alternate positions, starting from the rightmost position is 5+9 = 14. Difference between the two sums is 1 (=15-14).  Similarly, for the number 5798, the difference between  two sums, is 1.  Note: Read the input as a number and do entire processing as  a numberC++ compilers can compile C code alsoInput format First line contains the positive integerOutput format :First line should contain the difference between  the sum of the digits occuring in the alternate positions (starting from the first position) and the sum of the digits occuring in the alternate positions (startting from the last rightmost position).

Given a number find the absolute difference between left most and right most digit, and repeat it for second from left and second from right, and do repeat it until middle digit is met. Find the sum of those differences and if only one middle digit is available do add it to sum.Input Format:Accept an integer as an inputOutput Format:Print the calculated sumConstraints:1<= input <= 10^18 Note: Dont use arrays or strings to solve this problem statementSample Input 1:123456Sample Output 1:9Sample Input 2:39605447885Sample Output 2:17