Sure, here is a simple C program that calculates the sum of digits of a number using a while loop:

#include <stdio.h> int main() { int num, sum = 0, remainder; printf("Enter an integer\n"); scanf("%d", &num); while(num != 0) { remainder = num % 10; sum = sum + remainder; num = num / 10; } printf("Sum of digits of entered number = %d\n", sum); return 0; }

Here's how it works:

The program first asks the user to enter an integer.

It then enters a while loop, which continues until the number is not equal to 0.

Inside the loop, the program calculates the remainder of the number when divided by 10. This gives the last digit of the number.

The program then adds this remainder to the sum.

The number is then divided by 10, effectively removing the last digit.

Once the number is 0, the loop ends and the program prints the sum of the digits.

Question

Sure, here is a simple C program that calculates the sum of digits of a number using a while loop:

```c
#include <stdio.h>

int main() {
    int num, sum = 0, remainder;

printf("Enter an integer
");
    scanf("%d", &num);

while(num != 0) {
        remainder = num % 10;
        sum = sum + remainder;
        num = num / 10;
    }

printf("Sum of digits of entered number = %d
", sum);

return 0;
}
```

Here's how it works:

1. The program first asks the user to enter an integer.
2. It then enters a while loop, which continues until the number is not equal to 0.
3. Inside the loop, the program calculates the remainder of the number when divided by 10. This gives the last digit of the number.
4. The program then adds this remainder to the sum.
5. The number is then divided by 10, effectively removing the last digit.
6. Once the number is 0, the loop ends and the program prints the sum of the digits.

Knowee AI · Accepted Answer

Sure, here is a simple C program that calculates the sum of digits of a number using a while loop:

```c
#include <stdio.h>

int main() {
    int num, sum = 0, remainder;

printf("Enter an integer
");
    scanf("%d", &num);

while(num != 0) {
        remainder = num % 10;
        sum = sum + remainder;
        num = num / 10;
    }

printf("Sum of digits of entered number = %d
", sum);

return 0;
}
```

Here's how it works:

1. The program first asks the user to enter an integer.
2. It then enters a while loop, which continues until the number is not equal to 0.
3. Inside the loop, the program calculates the remainder of the number when divided by 10. This gives the last digit of the number.
4. The program then adds this remainder to the sum.
5. The number is then divided by 10, effectively removing the last digit.
6. Once the number is 0, the loop ends and the program prints the sum of the digits.

Write a C program to calculate sum of digits of a number. – using while loop

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Solution

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