Sure, here is a simple C program that uses a do-while loop to count the number of digits in a number:

#include <stdio.h> int main() { int num; int count = 0; printf("Enter a number: "); scanf("%d", &num); do { count++; num /= 10; } while (num != 0); printf("Number of digits: %d", count); return 0; }

Here's how it works:

The program first includes the standard input/output header file (stdio.h).

It then defines the main function where the program execution starts.

Inside the main function, it declares two integer variables: num (to store the user input) and count (to keep track of the number of digits).

It prompts the user to enter a number and stores the input in num.

It then enters a do-while loop. Inside the loop, it increments count by 1 and divides num by 10. This effectively removes the last digit from num.

The loop continues as long as num is not equal to 0. When num becomes 0, it means there are no more digits left to count.

Finally, it prints the number of digits stored in count and returns 0 to indicate successful program execution.

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Question

Sure, here is a simple C program that uses a do-while loop to count the number of digits in a number:

```c
#include <stdio.h>

int main() {
    int num;
    int count = 0;

printf("Enter a number: ");
    scanf("%d", &num);

do {
        count++;
        num /= 10;
    } while (num != 0);

printf("Number of digits: %d", count);

return 0;
}
```

Here's how it works:

1. The program first includes the standard input/output header file (`stdio.h`).
2. It then defines the `main` function where the program execution starts.
3. Inside the `main` function, it declares two integer variables: `num` (to store the user input) and `count` (to keep track of the number of digits).
4. It prompts the user to enter a number and stores the input in `num`.
5. It then enters a do-while loop. Inside the loop, it increments `count` by 1 and divides `num` by 10. This effectively removes the last digit from `num`.
6. The loop continues as long as `num` is not equal to 0. When `num` becomes 0, it means there are no more digits left to count.
7. Finally, it prints the number of digits stored in `count` and returns 0 to indicate successful program execution.

Knowee AI · Accepted Answer

Sure, here is a simple C program that uses a do-while loop to count the number of digits in a number:

```c
#include <stdio.h>

int main() {
    int num;
    int count = 0;

printf("Enter a number: ");
    scanf("%d", &num);

do {
        count++;
        num /= 10;
    } while (num != 0);

printf("Number of digits: %d", count);

return 0;
}
```

Here's how it works:

1. The program first includes the standard input/output header file (`stdio.h`).
2. It then defines the `main` function where the program execution starts.
3. Inside the `main` function, it declares two integer variables: `num` (to store the user input) and `count` (to keep track of the number of digits).
4. It prompts the user to enter a number and stores the input in `num`.
5. It then enters a do-while loop. Inside the loop, it increments `count` by 1 and divides `num` by 10. This effectively removes the last digit from `num`.
6. The loop continues as long as `num` is not equal to 0. When `num` becomes 0, it means there are no more digits left to count.
7. Finally, it prints the number of digits stored in `count` and returns 0 to indicate successful program execution.

Write a C program to count number of digits in a number. Using do-while loop

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