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Determine output:public class Test{ public static void main(String[] args){ int[] x = {1, 2, 3, 4}; int[] y = x; x = new int[2]; for(int i = 0; i < x.length; i++) System.out.print(y[i] + " "); }}123400001200

Question

Determine output:public class Test{ public static void main(String[] args){ int[] x = {1, 2, 3, 4}; int[] y = x; x = new int[2]; for(int i = 0; i < x.length; i++) System.out.print(y[i] + " "); }}123400001200

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Solution

The output of the given Java code will be "1 2".

Here's the step by step explanation:

  1. An integer array 'x' is declared and initialized with the values {1, 2, 3, 4}.

  2. Another integer array 'y' is declared and it is assigned the reference of array 'x'. So, both 'x' and 'y' point to the same array in memory.

  3. Then, a new array of size 2 is created and its reference is assigned to 'x'. Now, 'x' points to this new array while 'y' still points to the original array {1, 2, 3, 4}.

  4. A for loop is run for the length of 'x' (which is 2 now) and the elements of 'y' at the corresponding indices are printed. Since 'y' still points to the original array, the first two elements of the original array {1, 2, 3, 4} are printed, which are 1 and 2.

This problem has been solved

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