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Determine the output:public class Test{        public static void main(String[] args)                {                int[] x = {1, 2, 3, 4};                int[] y = x;                x = new int[2];                                for(int i = 0; i < x.length; i++)                        System.out.print(y[i] + " ");        }}Select one:a.1 2b.0 0c.0 0 0 0d.1 2 3 4

Question

Determine the output:public class Test{        public static void main(String[] args)                {                int[] x = {1, 2, 3, 4};                int[] y = x;                x = new int[2];                                for(int i = 0; i < x.length; i++)                        System.out.print(y[i] + " ");        }}Select one:a.1 2b.0 0c.0 0 0 0d.1 2 3 4

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Solution

The correct answer is a. 1 2

Here's the step-by-step explanation:

  1. An array x is created with the elements {1, 2, 3, 4}.
  2. A new array y is created and it references the same location as x. So, y also has the elements {1, 2, 3, 4}.
  3. Then, a new array is assigned to x with a length of 2. The elements of this new array are not specified, so they are initialized to the default value of 0. However, this does not affect y because y is still referencing the original array.
  4. A for loop is run for the length of x (which is 2), and the elements of y at the corresponding indices are printed. Since y is still referencing the original array, the output will be the first two elements of the original array, which are 1 and 2.

This problem has been solved

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