Determine output:public class Test{ public static void main(String[] args){ int[] x = {1, 2, 3, 4}; int[] y = x; x = new int[2]; for(int i = 0; i < x.length; i++) System.out.print(y[i] + " "); }}123400001200Clear ResponseSave & Next
Question
Determine output:public class Test{ public static void main(String[] args){ int[] x = {1, 2, 3, 4}; int[] y = x; x = new int[2]; for(int i = 0; i < x.length; i++) System.out.print(y[i] + " "); }}123400001200Clear ResponseSave & Next
Solution
The output of the given Java code will be "1 2".
Here's the step by step explanation:
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An integer array 'x' is declared and initialized with the values {1, 2, 3, 4}.
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Another integer array 'y' is declared and it is assigned the reference of array 'x'. So, both 'x' and 'y' are pointing to the same array in memory.
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Then, a new array of size 2 is created and its reference is assigned to 'x'. Now, 'x' is pointing to this new array. However, 'y' is still pointing to the original array {1, 2, 3, 4}.
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A for loop is used to iterate over the length of array 'x' (which is 2) and print the elements of array 'y' at the corresponding indices.
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Since 'y' is still pointing to the original array, the values printed will be the first two elements of the original array, which are 1 and 2.
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