public class Test{ public static void main(String[] args){ int[] x = {120, 200, 016 }; for(int i = 0; i < x.length; i++) System.out.print(x[i] + " "); }}
Question
public class Test{ public static void main(String[] args){ int[] x = {120, 200, 016 }; for(int i = 0; i < x.length; i++) System.out.print(x[i] + " "); }}
Solution
The given code is written in Java. It declares a class named Test with a main method. The main method is the entry point for any Java application.
Here's a step-by-step explanation of the code:
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public class Test{}: This line declares a public class namedTest. Thepublickeyword means that this class is accessible from any other class in the application. -
public static void main(String[] args){}: This line declares themainmethod. This method ispublic(meaning it can be accessed from any other class),static(meaning it belongs to theTestclass itself, rather than an instance of theTestclass), andvoid(meaning it doesn't return any value). Themainmethod takes one parameter: an array ofStringobjects. This array contains any command-line arguments that were passed when the application was started. -
int[] x = {120, 200, 016 };: This line declares an array of integers namedxand initializes it with three values. The third value is016, which is an octal (base-8) literal. In decimal (base-10), this value is 14. -
for(int i = 0; i < x.length; i++): This line starts aforloop that will iterate over each element in thexarray. The loop variableistarts at 0 and increases by 1 with each iteration of the loop. The loop continues as long asiis less than the length of thexarray. -
System.out.print(x[i] + " ");: This line is inside theforloop. It prints theith element of thexarray, followed by a space. TheSystem.out.printmethod does not add a newline character at the end, so all the elements of thexarray will be printed on the same line.
So, when you run this code, it will print 120 200 14 , because 016 in octal is 14 in decimal.
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