public class Test{ public static int x = 20; public static void fun(int arr[], int x){ while(x > arr.length){ x = x / 2; } for(int i=0;i<arr.length;i++){ arr[i] = x; } } public static void main(String[] args) { int[] a = {2,3,5,7,11}; int x = 100; fun(a,x); for(int i=0;i<a.length;i++){ System.out.print(a[i]+ " "); } System.out.println(x); }}
Question
public class Test{ public static int x = 20; public static void fun(int arr[], int x){ while(x > arr.length){ x = x / 2; } for(int i=0;i<arr.length;i++){ arr[i] = x; } } public static void main(String[] args) { int[] a = {2,3,5,7,11}; int x = 100; fun(a,x); for(int i=0;i<a.length;i++){ System.out.print(a[i]+ " "); } System.out.println(x); }}
Solution
This Java program defines a class named Test with a static integer variable x and a static method fun(). The fun() method takes an integer array and an integer as parameters. It then performs a loop where it divides the passed integer x by 2 until it is less than or equal to the length of the array. After that, it assigns the value of x to each element in the array.
In the main() method, an integer array a is defined with the elements {2,3,5,7,11}, and an integer x is defined with the value 100. The fun() method is then called with a and x as arguments. After the fun() method is executed, the program prints out each element in the array a followed by the value of x.
However, it's important to note that the x printed at the end of the main() method is the local x (value 100), not the x that was passed to and modified in the fun() method. This is because Java is pass-by-value, meaning that changing the value of x inside the fun() method does not affect the value of x in the main() method.
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