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public static void main(String[] args){  for (int i = 3; i <= 7; i++) {int num;if(i%2 == 0){num = 0;  for (int j = 1; j <= 4; j++)  {  System.out.print(num);  num = (num == 0)? 3 : 2;  }} else {num = 1;  for (int j = 1; j <= 3; j++){System.out.print(num);num = (num == 0)? 2 : 5;}  }  System.out.println();}}

Question

public static void main(String[] args){  for (int i = 3; i <= 7; i++) {int num;if(i%2 == 0){num = 0;  for (int j = 1; j <= 4; j++)  {  System.out.print(num);  num = (num == 0)? 3 : 2;  }} else {num = 1;  for (int j = 1; j <= 3; j++){System.out.print(num);num = (num == 0)? 2 : 5;}  }  System.out.println();}}

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Solution

The given code snippet is written in Java.

The code defines a public static void main method, which is the entry point of a Java program. It takes an array of strings as an argument.

Inside the main method, there is

Similar Questions

Select the correct answerPredict the output?public class Main {  public static void main(String args[]) {    int arr[][] = new int[4][];    arr[0] = new int[1];    arr[1] = new int[2];    arr[2] = new int[3];    arr[3] = new int[4];      int i, j, k = 0;    for (i = 0; i < 4; i++) {      for (j = 0; j < i + 1; j++) {        arr[i][j] = k;        k++;      }    }    for (i = 0; i < 4; i++) {      for (j = 0; j < i + 1; j++) {        System.out.print(" " + arr[i][j]);        k++;      }      System.out.println();    }  }} Options 0 0 0 0 0 0 0 0 0 0 0 1 2 3 4 5 6 7 8 9 Compiler Error 9 7 8 4 5 6 0 1 2 3

Given1. class Program{2. 3.     public static void main(String[] args){4. 5.         int val1 = 1;6.         int val2 = 2;7. 8.         if(val1 == val2)9.              System.out.print("1");10.         if(val1!= val2)11.              System.out.print("2");12.         if(val1 > val2)13.              System.out.print("3");14.         if(val1 < val2)15.             System.out.print(4);16.         if(val1 => val2)17.             System.out.print("5");18. 19.     }20. }     Which is the output?*24524Compilation fails due to an error on line 16Compilation fails due to multiple errorsNone of above.

Determine output:public class Test{ public static void main(String args[]){ int i; for(i = 1; i < 6; i++){ if(i > 3) continue ; } System.out.println(i); }}23466

Determine output:public class Test{ public static void main(String args[]){ int i, j; for(i=1, j=0;i<10;i++) j += i; System.out.println(i); }}1011920

public class Main { public static int ElementsAndIndices(int[] arr) { if (arr == null || arr.length == 0) { return -1; } int count = 0; for (int i = 0; i < arr.length; i++) { if (arr[i] == i) { count++; } } return count; } public static void main(String[] args) { int[] arr = {10, 1, 12, 3, 5, 8, 9, 7, 12, 23}; System.out.println(ElementsAndIndices(arr)); // Output: 3 int[] arr2 = {-3, 0, 1, 3, 5, 7}; System.out.println(ElementsAndIndices(arr2)); // Output: 1 } } :6: error: cannot find symbol int result = ElementsAndIndices(arr); ^ symbol: method ElementsAndIndices(int[]) location: class SolutionClass 1 error it is showing this error

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