For a compressor with μ = 191, determine the expanded voltage gain if the input voltage Vin is 0.32Vmax.Express your answers in 4 decimal places.

To determine the expanded voltage gain for the given compressor, we need to use the provided parameters and follow the steps below:

1. Identify the given parameters:

   • μ (mu) = 191
   • Vin = 0.32Vmax

2. Use the formula for the expanded voltage gain in a compressor: $G = \frac{\ln(1 + \mu \cdot |Vin|)}{\ln(1 + \mu)}$

3. Substitute the given values into the formula: $G = \frac{\ln(1 + 191 \cdot 0.32Vmax)}{\ln(1 + 191)}$

4. Simplify the expression inside the logarithms: $G = \frac{\ln(1 + 61.12Vmax)}{\ln(192)}$

5. Since Vmax is a constant and does not affect the ratio, we can simplify further by considering the numerical values: $G = \frac{\ln(1 + 61.12)}{\ln(192)}$

6. Calculate the natural logarithms: $\ln(1 + 61.12) = \ln(62.12) \approx 4.1295$ $\ln(192) \approx 5.2575$

7. Divide the results to find the expanded voltage gain: $G = \frac{4.1295}{5.2575} \approx 0.7855$

Therefore, the expanded voltage gain is approximately 0.7855.