38. An ideal gas occupying a 2.0 L flask at 1.0 atm is allowed to expand to a volume of 6000 mL. Calculate the final pressure.*1 point0.33 atm0.00033 atm2.0 atm12000 atm
Question
- An ideal gas occupying a 2.0 L flask at 1.0 atm is allowed to expand to a volume of 6000 mL. Calculate the final pressure.*1 point0.33 atm0.00033 atm2.0 atm12000 atm
Solution
The problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant.
Boyle's Law formula is P1V1 = P2V2, where:
P1 = initial pressure V1 = initial volume P2 = final pressure V2 = final volume
Given in the problem:
P1 = 1.0 atm V1 = 2.0 L V2 = 6000 mL = 6.0 L (since 1 L = 1000 mL)
We need to find P2.
Substituting the given values into Boyle's Law formula:
1.0 atm * 2.0 L = P2 * 6.0 L
Solving for P2 gives:
P2 = (1.0 atm * 2.0 L) / 6.0 L = 0.33 atm
So, the final pressure of the gas after expansion is 0.33 atm.
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