A gas sample of argon, maintained at constant temperature, occupies a volume of 500 L at 4.00 atm. What is the new volume if the pressure were charged to 8 atm?*1 point500 L250 L125 L62.5 L
Question
A gas sample of argon, maintained at constant temperature, occupies a volume of 500 L at 4.00 atm. What is the new volume if the pressure were charged to 8 atm?*1 point500 L250 L125 L62.5 L
Solution
This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant.
Boyle's Law formula is P1V1 = P2V2, where:
P1 = initial pressure V1 = initial volume P2 = final pressure V2 = final volume
Given in the problem:
P1 = 4.00 atm (initial pressure) V1 = 500 L (initial volume) P2 = 8 atm (final pressure) V2 = ? (final volume we're solving for)
Substitute the known values into Boyle's Law:
(4.00 atm * 500 L) = (8 atm * V2)
Solving for V2 gives:
V2 = (4.00 atm * 500 L) / 8 atm = 250 L
So, the new volume of the gas, if the pressure were changed to 8 atm, would be 250 L.
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