A gas is initially at a pressure of 2 atm and a volume of 4 L. If the volume is decreased to 2 L while the temperature is held constant, what will be the new pressure of the gas, according to Boyle's Law?(2 Points)1 atm2 atmC) 4 atmD) 8 atm
Question
A gas is initially at a pressure of 2 atm and a volume of 4 L. If the volume is decreased to 2 L while the temperature is held constant, what will be the new pressure of the gas, according to Boyle's Law?(2 Points)1 atm2 atmC) 4 atmD) 8 atm
Solution
Boyle's Law states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. This means that if the volume decreases, the pressure increases and vice versa.
The formula for Boyle's Law is P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Given in the problem, P1 = 2 atm, V1 = 4 L, and V2 = 2 L. We are asked to solve for P2.
Substituting the given values into the formula, we get:
2 atm * 4 L = P2 * 2 L
Solving for P2, we get:
P2 = (2 atm * 4 L) / 2 L = 4 atm
So, the new pressure of the gas, according to Boyle's Law, is 4 atm. Therefore, the correct answer is C) 4 atm.
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