A gas container holds 2 moles of an ideal gas at a pressure of 1 atm and a temperature of 300 K. If the temperature is raised to 600 K with the volume kept constant, what is the new pressure inside the container?Select one:a.8 atmb.4 atmc.2 atmd.1 atm
Question
A gas container holds 2 moles of an ideal gas at a pressure of 1 atm and a temperature of 300 K. If the temperature is raised to 600 K with the volume kept constant, what is the new pressure inside the container?Select one:a.8 atmb.4 atmc.2 atmd.1 atm
Solution
To solve this problem, we can use the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature if the volume and the amount of gas are kept constant. This relationship can be expressed as P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.
Given in the problem, we have:
P1 = 1 atm T1 = 300 K T2 = 600 K
We need to find P2.
Substituting the given values into the equation, we get:
1/300 = P2/600
Solving for P2, we get:
P2 = 2 atm
So, the new pressure inside the container is 2 atm. Therefore, the correct answer is c. 2 atm.
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