To solve this problem, we can use the combined gas law which states that the ratio of the product of initial pressure and volume to the initial temperature is equal to the ratio of the product of final pressure and volume to the final temperature. Mathematically, this can be expressed as:

(P1*V1)/T1 = (P2*V2)/T2

Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (what we're trying to find)
V2 = final volume
T2 = final temperature

Given in the problem are:
P1 = 1.2 atm
V1 = 2.0 L
T1 = 50 K
V2 = 3.0 L
T2 = 100 K

We can plug these values into the combined gas law equation and solve for P2:

(1.2 atm * 2.0 L) / 50 K = (P2 * 3.0 L) / 100 K

Solving for P2 gives:

P2 = (1.2 atm * 2.0 L * 100 K) / (50 K * 3.0 L) = 1.6 atm

So, the new pressure of the gas is 1.6 atm.

Question

To solve this problem, we can use the combined gas law which states that the ratio of the product of initial pressure and volume to the initial temperature is equal to the ratio of the product of final pressure and volume to the final temperature. Mathematically, this can be expressed as:

(P1*V1)/T1 = (P2*V2)/T2

Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (what we're trying to find)
V2 = final volume
T2 = final temperature

Given in the problem are:
P1 = 1.2 atm
V1 = 2.0 L
T1 = 50 K
V2 = 3.0 L
T2 = 100 K

We can plug these values into the combined gas law equation and solve for P2:

(1.2 atm * 2.0 L) / 50 K = (P2 * 3.0 L) / 100 K

Solving for P2 gives:

P2 = (1.2 atm * 2.0 L * 100 K) / (50 K * 3.0 L) = 1.6 atm

So, the new pressure of the gas is 1.6 atm.

Knowee AI · Accepted Answer

To solve this problem, we can use the combined gas law which states that the ratio of the product of initial pressure and volume to the initial temperature is equal to the ratio of the product of final pressure and volume to the final temperature. Mathematically, this can be expressed as:

(P1*V1)/T1 = (P2*V2)/T2

Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (what we're trying to find)
V2 = final volume
T2 = final temperature

Given in the problem are:
P1 = 1.2 atm
V1 = 2.0 L
T1 = 50 K
V2 = 3.0 L
T2 = 100 K

We can plug these values into the combined gas law equation and solve for P2:

(1.2 atm * 2.0 L) / 50 K = (P2 * 3.0 L) / 100 K

Solving for P2 gives:

P2 = (1.2 atm * 2.0 L * 100 K) / (50 K * 3.0 L) = 1.6 atm

So, the new pressure of the gas is 1.6 atm.

A sample of gas was heated 50 K initially and increased to 100 K within a given time. The volume is also increased from 2.0L to 3.0L. If the original pressure was 1.2 atm, what is the new pressure?

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