Find the output voltage (approx.) Vout, if Vin = 35 mV, R1= 950 ohm, R2 = 235 kohm
Question
Find the output voltage (approx.) Vout, if Vin = 35 mV, R1= 950 ohm, R2 = 235 kohm
Solution
The output voltage can be found using the formula for a voltage divider, which is:
Vout = Vin * (R2 / (R1 + R2))
Substituting the given values into the formula, we get:
Vout = 35mV * (235kΩ / (950Ω + 235kΩ))
First, let's convert the resistances to the same units for easy calculation. 1kΩ is equal to 1000Ω, so 235kΩ is equal to 235000Ω.
So, the formula becomes:
Vout = 35mV * (235000Ω / (950Ω + 235000Ω))
Adding 950Ω and 235000Ω gives 235950Ω.
So, the formula becomes:
Vout = 35mV * (235000Ω / 235950Ω)
Performing the division gives approximately 0.99596.
So, the formula becomes:
Vout = 35mV * 0.99596
Multiplying 35mV by 0.99596 gives approximately 34.8586mV.
So, the output voltage Vout is approximately 34.8586mV.
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