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¡An OPAMP has differential voltage gain of 100,000 and CMRR of 60 dB.  If non inverting input voltage is 150 μV and inverting input voltage is 140 μV, calculate the output voltage of OPAMP(1 Point)1.010v2.030.5v

Question

¡An OPAMP has differential voltage gain of 100,000 and CMRR of 60 dB.  If non inverting input voltage is 150 μV and inverting input voltage is 140 μV, calculate the output voltage of OPAMP(1 Point)1.010v2.030.5v

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Solution

To calculate the output voltage of the OPAMP, we need to consider both the differential voltage gain and the common mode rejection ratio (CMRR).

Step 1: Convert the CMRR from dB to a ratio. The formula to convert from dB to a ratio is:

CMRR_ratio = 10^(CMRR_dB/20)

So, CMRR_ratio = 10^(60/20) = 1000

Step 2: Calculate the differential voltage (Vd) and the common mode voltage (Vcm).

Vd = Vin+ - Vin- = 150μV - 140μV = 10μV

Vcm = (Vin+ + Vin-) / 2 = (150μV + 140μV) / 2 = 145μV

Step 3: Calculate the output voltage (Vout). The formula for the output voltage is:

Vout = Ad*Vd + (1/CMRR_ratio)*Vcm

Where Ad is the differential voltage gain.

So, Vout = 100,000*10μV + (1/1000)*145μV = 1V + 0.145mV = 1.000145V

So, the output voltage of the OPAMP is approximately 1.000145V.

This problem has been solved

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