Knowee
Questions
Features
Study Tools

How much primary antibody should be added to prepare 14 mL solution of primary antibody with a dilution of 1:500?14 µL2.8 µL1.4 µL28 µL

Question

How much primary antibody should be added to prepare 14 mL solution of primary antibody with a dilution of 1:500?14 µL2.8 µL1.4 µL28 µL

🧐 Not the exact question you are looking for?Go ask a question

Solution

To prepare a 14 mL solution of primary antibody with a dilution of 1:500, you need to add 28 µL of primary antibody.

Here's the step-by-step calculation:

  1. A 1:500 dilution means 1 part of the primary antibody is mixed with 499 parts of the diluent to make a total of 500 parts.

  2. To find out how much primary antibody you need for 14 mL (or 14,000 µL, since 1 mL = 1,000 µL), you divide 14,000 µL by 500.

  3. 14,000 µL / 500 = 28 µL

So, you need 28 µL of primary antibody.

This problem has been solved

Similar Questions

Which of the following is a 1:4 dilution?Group of answer choices15 uL PBS + 5 uL antibody16 uL PBS + 4 uL antibody20 uL PBS + 5 uL antibody20 uL PBS + 4 uL antibody

You have 220mL of a 10% solution (w/v). You need to prepare a 1:200 solution. Howmuch diluent will you add to the stock solution?

Your solution is 10000 times more dilute than the original bacterial sample (ie 1x10-4). Your take 0.5ml of this solution and add it to 4.5ml saline. Once mixed, 0.5ml of that diluted cell suspension is placed in another tube with 4.5 ml of sterile saline. How many times is the original cell suspension diluted now? (Please type your numerical answer eg 1 or 10 or 100 or 1000 etc)

You have prepared a 2 M stock solution of an analyte you will be diluting to prepare your standard solutions.  What volume (in mL) will you need to add and dilute in a 250 mL volumetric flask to achieve a final concentration of 0.06 M?  Answer to 1 decimal place (Hint: C1V1=C2V2)

If you were making a 1:10 dilution of a 100mM NaCl solution what will be its final concentration?

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.