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You have prepared a 2 M stock solution of an analyte you will be diluting to prepare your standard solutions.  What volume (in mL) will you need to add and dilute in a 250 mL volumetric flask to achieve a final concentration of 0.06 M?  Answer to 1 decimal place (Hint: C1V1=C2V2)

Question

You have prepared a 2 M stock solution of an analyte you will be diluting to prepare your standard solutions.  What volume (in mL) will you need to add and dilute in a 250 mL volumetric flask to achieve a final concentration of 0.06 M?  Answer to 1 decimal place (Hint: C1V1=C2V2)

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Solution

To solve this problem, we will use the formula C1V1 = C2V2, where:

C1 = initial concentration V1 = initial volume C2 = final concentration V2 = final volume

We are asked to find V1, so we rearrange the formula to solve for V1:

V1 = C2V2 / C1

Substituting the given values:

V1 = (0.06 M * 250 mL) / 2 M

V1 = 15 mL

So, you will need to add 15 mL of the 2 M stock solution to the 250 mL volumetric flask and then dilute with solvent up to the 250 mL mark to achieve a final concentration of 0.06 M.

This problem has been solved

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To get 2 mL of 0.625 M solution, take 0.5 mL of the second diluted solution (0.625 M) and add it to 1.5 mL of solvent. Detailed Procedure First Dilution: Take 1 mL of the 10.01 M stock solution and add 3 mL of solvent (water) in Tube 1. Mix thoroughly to get 4 mL of 2.5025 M solution. Second Dilution: Take 1 mL of the 2.5025 M solution from Tube 1 and add 3 mL of solvent in Tube 2. Mix thoroughly to get 4 mL of approximately 0.625 M solution. Final Preparation: Take 0.5 mL of the 0.625 M solution from Tube 2 and add 1.5 mL of solvent in Tube 3. Mix thoroughly to get 2 mL of 0.625 M solution.

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