To get 2 mL of 0.625 M solution, take 0.5 mL of the second diluted solution (0.625 M) and add it to 1.5 mL of solvent. Detailed Procedure First Dilution: Take 1 mL of the 10.01 M stock solution and add 3 mL of solvent (water) in Tube 1. Mix thoroughly to get 4 mL of 2.5025 M solution. Second Dilution: Take 1 mL of the 2.5025 M solution from Tube 1 and add 3 mL of solvent in Tube 2. Mix thoroughly to get 4 mL of approximately 0.625 M solution. Final Preparation: Take 0.5 mL of the 0.625 M solution from Tube 2 and add 1.5 mL of solvent in Tube 3. Mix thoroughly to get 2 mL of 0.625 M solution.

You have prepared a 2 M stock solution of an analyte you will be diluting to prepare your standard solutions.  What volume (in mL) will you need to add and dilute in a 250 mL volumetric flask to achieve a final concentration of 0.06 M?  Answer to 1 decimal place (Hint: C1V1=C2V2)

If you add 1.0 ml of a colored solution (Stock) to 4.0 ml of water in a test tube, what is the dilution ratio, of the colored solution to the final volume?

You have 220mL of a 10% solution (w/v). You need to prepare a 1:200 solution. Howmuch diluent will you add to the stock solution?

ow would you make a 10x sample dilution to a total volume of 1 ml? For this Eppendorf tubes and micropipettes (±1% repeatability) are available.Transfer µl of 10x sample solution to the Eppendorf tube and add µl of .The combined error introduced in the final sample dilution would then be %.

Your solution is 10000 times more dilute than the original bacterial sample (ie 1x10-4). Your take 0.5ml of this solution and add it to 4.5ml saline. Once mixed, 0.5ml of that diluted cell suspension is placed in another tube with 4.5 ml of sterile saline. How many times is the original cell suspension diluted now? (Please type your numerical answer eg 1 or 10 or 100 or 1000 etc)