You wish to prepare 140.0 mL of a 3.0 M solution of NaOH by diluting a concentrated 10.0 M NaOH solution. What volume of the concentrated solution is required to do this?Group of answer choicesGroup of answer choices42 mL7.0 mL0.47 mL20 mL
Question
You wish to prepare 140.0 mL of a 3.0 M solution of NaOH by diluting a concentrated 10.0 M NaOH solution. What volume of the concentrated solution is required to do this?Group of answer choicesGroup of answer choices42 mL7.0 mL0.47 mL20 mL
Solution
To solve this problem, you can use the formula M1V1 = M2V2, where M1 is the molarity of the concentrated solution, V1 is the volume of the concentrated solution, M2 is the molarity of the diluted solution, and V2 is the volume of the diluted solution.
Given: M1 = 10.0 M (concentration of the concentrated solution) M2 = 3.0 M (concentration of the diluted solution) V2 = 140.0 mL (volume of the diluted solution)
We need to find V1 (volume of the concentrated solution).
Rearranging the formula to solve for V1 gives us V1 = M2V2 / M1.
Substituting the given values into the formula gives us V1 = (3.0 M * 140.0 mL) / 10.0 M = 42 mL.
Therefore, you would need 42 mL of the concentrated solution to prepare 140.0 mL of a 3.0 M solution of NaOH.
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