A train accelerates from 36 km/h to 54 km/h in 10 sec.(i) Acceleration
Question
A train accelerates from 36 km/h to 54 km/h in 10 sec.(i) Acceleration
Solution
To calculate acceleration, we first need to convert the speeds from km/h to m/s because the standard unit of acceleration is m/s².
1 km/h = 5/18 m/s
So,
Initial speed (u) = 36 km/h = 36 * 5/18 = 10 m/s Final speed (v) = 54 km/h = 54 * 5/18 = 15 m/s Time (t) = 10 sec
Acceleration (a) is defined as the rate of change of velocity per unit of time. It can be calculated using the formula:
a = (v - u) / t
Substituting the given values into the formula, we get:
a = (15 m/s - 10 m/s) / 10 sec = 0.5 m/s²
So, the acceleration of the train is 0.5 m/s².
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