Sure, let's solve the problem step by step.

Given:
- Initial speed of the train, $ u = 8 \, \text{m/s} $
- Acceleration, $ a = -0.5 \, \text{m/s}^2 $

We need to determine the speed of the train after 1 second, 2 seconds, and 5 seconds.

We can use the equation of motion:
$$ v = u + at $$

1. **After 1 second:**
$$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 1 \, \text{s}) $$
$$ v = 8 \, \text{m/s} - 0.5 \, \text{m/s} $$
$$ v = 7.5 \, \text{m/s} $$

2. **After 2 seconds:**
$$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 2 \, \text{s}) $$
$$ v = 8 \, \text{m/s} - 1 \, \text{m/s} $$
$$ v = 7 \, \text{m/s} $$

3. **After 5 seconds:**
$$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 5 \, \text{s}) $$
$$ v = 8 \, \text{m/s} - 2.5 \, \text{m/s} $$
$$ v = 5.5 \, \text{m/s} $$

So, the speed of the train after 1 second is 7.5 m/s, after 2 seconds is 7 m/s, and after 5 seconds is 5.5 m/s.

Question

Sure, let's solve the problem step by step.

Given:
- Initial speed of the train, $ u = 8 \, \text{m/s} $
- Acceleration, $ a = -0.5 \, \text{m/s}^2 $

We need to determine the speed of the train after 1 second, 2 seconds, and 5 seconds.

We can use the equation of motion:
$$ v = u + at $$

1. **After 1 second:**
   $$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 1 \, \text{s}) $$
   $$ v = 8 \, \text{m/s} - 0.5 \, \text{m/s} $$
   $$ v = 7.5 \, \text{m/s} $$

2. **After 2 seconds:**
   $$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 2 \, \text{s}) $$
   $$ v = 8 \, \text{m/s} - 1 \, \text{m/s} $$
   $$ v = 7 \, \text{m/s} $$

3. **After 5 seconds:**
   $$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 5 \, \text{s}) $$
   $$ v = 8 \, \text{m/s} - 2.5 \, \text{m/s} $$
   $$ v = 5.5 \, \text{m/s} $$

So, the speed of the train after 1 second is 7.5 m/s, after 2 seconds is 7 m/s, and after 5 seconds is 5.5 m/s.

Knowee AI · Accepted Answer

Sure, let's solve the problem step by step.

Given:
- Initial speed of the train, $ u = 8 \, \text{m/s} $
- Acceleration, $ a = -0.5 \, \text{m/s}^2 $

We need to determine the speed of the train after 1 second, 2 seconds, and 5 seconds.

We can use the equation of motion:
$$ v = u + at $$

1. **After 1 second:**
   $$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 1 \, \text{s}) $$
   $$ v = 8 \, \text{m/s} - 0.5 \, \text{m/s} $$
   $$ v = 7.5 \, \text{m/s} $$

2. **After 2 seconds:**
   $$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 2 \, \text{s}) $$
   $$ v = 8 \, \text{m/s} - 1 \, \text{m/s} $$
   $$ v = 7 \, \text{m/s} $$

3. **After 5 seconds:**
   $$ v = 8 \, \text{m/s} + (-0.5 \, \text{m/s}^2 \times 5 \, \text{s}) $$
   $$ v = 8 \, \text{m/s} - 2.5 \, \text{m/s} $$
   $$ v = 5.5 \, \text{m/s} $$

So, the speed of the train after 1 second is 7.5 m/s, after 2 seconds is 7 m/s, and after 5 seconds is 5.5 m/s.

The train gets up to 8 m/s along the same straight track. The driver applies the brakes causing the train to accelerate at –0.5 m/s/s.Determine its speed after 1 second, 2 seconds, and 5 seconds.

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