To solve this problem, we need to use the formula for distance travelled in nth second which is given by:

s_n = u + a/2(2n-1)

where:
s_n is the distance travelled in nth second,
u is the initial velocity,
a is the acceleration, and
n is the nth second.

However, before we can use this formula, we need to convert the initial velocity from kmph to m/s. We can do this by multiplying the kmph value by 5/18.

So, the initial velocity u in m/s is 54 * 5/18 = 15 m/s.

Now we can substitute the values into the formula:

s_5 = 15 + 5/2(2*5 - 1)
s_5 = 15 + 2.5(9)
s_5 = 15 + 22.5
s_5 = 37.5 m

So, the train travels 37.5 meters in the 5th second of its journey. The correct answer is B) 37.5 m.

Question

To solve this problem, we need to use the formula for distance travelled in nth second which is given by:

s_n = u + a/2(2n-1)

where:
s_n is the distance travelled in nth second,
u is the initial velocity,
a is the acceleration, and
n is the nth second.

However, before we can use this formula, we need to convert the initial velocity from kmph to m/s. We can do this by multiplying the kmph value by 5/18.

So, the initial velocity u in m/s is 54 * 5/18 = 15 m/s.

Now we can substitute the values into the formula:

s_5 = 15 + 5/2(2*5 - 1)
s_5 = 15 + 2.5(9)
s_5 = 15 + 22.5
s_5 = 37.5 m

So, the train travels 37.5 meters in the 5th second of its journey. The correct answer is B) 37.5 m.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for distance travelled in nth second which is given by:

s_n = u + a/2(2n-1)

where:
s_n is the distance travelled in nth second,
u is the initial velocity,
a is the acceleration, and
n is the nth second.

However, before we can use this formula, we need to convert the initial velocity from kmph to m/s. We can do this by multiplying the kmph value by 5/18.

So, the initial velocity u in m/s is 54 * 5/18 = 15 m/s.

Now we can substitute the values into the formula:

s_5 = 15 + 5/2(2*5 - 1)
s_5 = 15 + 2.5(9)
s_5 = 15 + 22.5
s_5 = 37.5 m

So, the train travels 37.5 meters in the 5th second of its journey. The correct answer is B) 37.5 m.

A train is moving with a velocity of 54 kmph. It is accelerated at the rate 5m/s2. Find the distance travelled by the train in the 5th second of its journey.A 30 m B 37.5 m C 40 m D 47.5 m

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