A man travelled a certain distance by train at the rate of 25 kmph. and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was ?25 km 30 km 20 km 15 km
Question
A man travelled a certain distance by train at the rate of 25 kmph. and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was ?25 km 30 km 20 km 15 km
Solution
Let's solve this step by step:
Step 1: Convert the total time of the journey from hours and minutes to hours. 5 hours 48 minutes = 5.8 hours.
Step 2: Let's denote the distance travelled by train as 'd' km. The time taken to travel this distance by train is d/25 hours and the time taken to walk back the same distance is d/4 hours.
Step 3: According to the problem, the sum of these two times is equal to the total time of the journey. So, we can write the equation as follows: d/25 + d/4 = 5.8
Step 4: To solve for 'd', we first need to get rid of the fractions by multiplying the entire equation by 100. This gives us: 4d + 25d = 580
Step 5: Simplify the equation to find 'd': 29d = 580
Step 6: Solve for 'd': d = 580 / 29 = 20 km
So, the distance travelled was 20 km.
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