The line of symmetry for a parabolic curve given by the equation y = ax^2 + bx + c is x = -b/2a.

In the given equation y = 5x^2 + 1, the coefficient a is 5 and there is no x term, so b = 0.

Substituting these values into the formula, we get x = -0/(2*5) = 0.

So, the line of symmetry of the curve y = 5x^2 + 1 is x = 0.

Question

The line of symmetry for a parabolic curve given by the equation y = ax^2 + bx + c is x = -b/2a.

In the given equation y = 5x^2 + 1, the coefficient a is 5 and there is no x term, so b = 0.

Substituting these values into the formula, we get x = -0/(2*5) = 0.

So, the line of symmetry of the curve y = 5x^2 + 1 is x = 0.

Knowee AI · Accepted Answer

The line of symmetry for a parabolic curve given by the equation y = ax^2 + bx + c is x = -b/2a.

In the given equation y = 5x^2 + 1, the coefficient a is 5 and there is no x term, so b = 0.

Substituting these values into the formula, we get x = -0/(2*5) = 0.

So, the line of symmetry of the curve y = 5x^2 + 1 is x = 0.

Find the line of symmetry of the curve y=5x2+1.