The line of symmetry for a parabola given by the equation y = ax^2 + bx + c is x = -b/2a.

In the equation y = -5x^2 + 11, a = -5 and b = 0 (since there is no x term).

So, the line of symmetry is x = -0/(2*-5) = 0.

Therefore, the line of symmetry of the curve y = -5x^2 + 11 is x = 0.

Question

The line of symmetry for a parabola given by the equation y = ax^2 + bx + c is x = -b/2a.

In the equation y = -5x^2 + 11, a = -5 and b = 0 (since there is no x term).

So, the line of symmetry is x = -0/(2*-5) = 0.

Therefore, the line of symmetry of the curve y = -5x^2 + 11 is x = 0.

Knowee AI · Accepted Answer

The line of symmetry for a parabola given by the equation y = ax^2 + bx + c is x = -b/2a.

In the equation y = -5x^2 + 11, a = -5 and b = 0 (since there is no x term).

So, the line of symmetry is x = -0/(2*-5) = 0.

Therefore, the line of symmetry of the curve y = -5x^2 + 11 is x = 0.

Find the line of symmetry of the curve y=−5x2+11.