The pH of a sample containing 0.0125 M solution of potassium hydroxide (KOH) isA. 1.90B. 3.61C. 12.10D. 13.98

To answer this question, we first need to understand that potassium hydroxide (KOH) is a strong base. This means it will dissociate completely in water to form K+ and OH- ions.

The concentration of OH- ions will be the same as the original concentration of KOH, which is 0.0125 M.

We can use the formula for pOH, which is -log[OH-].

pOH = -log(0.0125) = 1.90

However, the question asks for pH, not pOH. We know that pH + pOH = 14 at 25 degrees Celsius.

So, we can subtract our pOH from 14 to find the pH.

pH = 14 - pOH = 14 - 1.90 = 12.10

So, the pH of the solution is 12.10. The correct answer is C. 12.10.